11984831250937 has 2 divisors, whose sum is σ = 11984831250938. Its totient is φ = 11984831250936.

The previous prime is 11984831250883. The next prime is 11984831250947. The reversal of 11984831250937 is 73905213848911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10630019057641 + 1354812193296 = 3260371^2 + 1163964^2 .

It is a cyclic number.

It is not a de Polignac number, because 11984831250937 - 2⁴³ = 3188738228729 is a prime.

It is a super-2 number, since 2×11984831250937² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11984831250947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5992415625468 + 5992415625469.

It is an arithmetic number, because the mean of its divisors is an integer number (5992415625469).

Almost surely, 2^{11984831250937} is an apocalyptic number.

It is an amenable number.

11984831250937 is a deficient number, since it is larger than the sum of its proper divisors (1).

11984831250937 is an equidigital number, since it uses as much as digits as its factorization.

11984831250937 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13063680, while the sum is 61.

The spelling of 11984831250937 in words is "eleven trillion, nine hundred eighty-four billion, eight hundred thirty-one million, two hundred fifty thousand, nine hundred thirty-seven".