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119899873 is a prime number
BaseRepresentation
bin1110010010110…
…00011011100001
322100121112201001
413021120123201
5221143243443
615521512001
72654063212
oct711303341
9270545631
10119899873
1161753605
12341a2601
131bac0492
1411cd1409
15a7d5d4d
hex72586e1

119899873 has 2 divisors, whose sum is σ = 119899874. Its totient is φ = 119899872.

The previous prime is 119899837. The next prime is 119899903. The reversal of 119899873 is 378998911.

Together with previous prime (119899837) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105822369 + 14077504 = 10287^2 + 3752^2 .

It is an emirp because it is prime and its reverse (378998911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119899873 - 217 = 119768801 is a prime.

It is a super-2 number, since 2×1198998732 = 28751959090832258, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (119899973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59949936 + 59949937.

It is an arithmetic number, because the mean of its divisors is an integer number (59949937).

Almost surely, 2119899873 is an apocalyptic number.

It is an amenable number.

119899873 is a deficient number, since it is larger than the sum of its proper divisors (1).

119899873 is an equidigital number, since it uses as much as digits as its factorization.

119899873 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 979776, while the sum is 55.

The square root of 119899873 is about 10949.8800450051. The cubic root of 119899873 is about 493.1051909060.

The spelling of 119899873 in words is "one hundred nineteen million, eight hundred ninety-nine thousand, eight hundred seventy-three".