119901976965643 has 2 divisors, whose sum is σ = 119901976965644. Its totient is φ = 119901976965642.

The previous prime is 119901976965629. The next prime is 119901976965649. The reversal of 119901976965643 is 346569679109911.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 119901976965643 - 2²¹ = 119901974868491 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 119901976965643.

It is not a weakly prime, because it can be changed into another prime (119901976965649) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59950988482821 + 59950988482822.

It is an arithmetic number, because the mean of its divisors is an integer number (59950988482822).

Almost surely, 2^{119901976965643} is an apocalyptic number.

119901976965643 is a deficient number, since it is larger than the sum of its proper divisors (1).

119901976965643 is an equidigital number, since it uses as much as digits as its factorization.

119901976965643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 595213920, while the sum is 76.

The spelling of 119901976965643 in words is "one hundred nineteen trillion, nine hundred one billion, nine hundred seventy-six million, nine hundred sixty-five thousand, six hundred forty-three".