Base | Representation |
---|---|
bin | 10001011100110000110… |
… | …111100000100001101001 |
3 | 11020122010102210200211102 |
4 | 101130300313200201221 |
5 | 124121242111424342 |
6 | 2314511031411145 |
7 | 152430130362302 |
oct | 21346067404151 |
9 | 4218112720742 |
10 | 1199115733097 |
11 | 4225a66302a7 |
12 | 174491523ab5 |
13 | 890cb33c559 |
14 | 42074d057a9 |
15 | 212d226a832 |
hex | 11730de0869 |
1199115733097 has 2 divisors, whose sum is σ = 1199115733098. Its totient is φ = 1199115733096.
The previous prime is 1199115733043. The next prime is 1199115733103. The reversal of 1199115733097 is 7903375119911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 877639206976 + 321476526121 = 936824^2 + 566989^2 .
It is a cyclic number.
It is not a de Polignac number, because 1199115733097 - 26 = 1199115733033 is a prime.
It is a super-2 number, since 2×11991157330972 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1199115733007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 599557866548 + 599557866549.
It is an arithmetic number, because the mean of its divisors is an integer number (599557866549).
Almost surely, 21199115733097 is an apocalyptic number.
It is an amenable number.
1199115733097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1199115733097 is an equidigital number, since it uses as much as digits as its factorization.
1199115733097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1607445, while the sum is 56.
The spelling of 1199115733097 in words is "one trillion, one hundred ninety-nine billion, one hundred fifteen million, seven hundred thirty-three thousand, ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •