Base | Representation |
---|---|
bin | 101101101111… |
… | …100100000101 |
3 | 211120012222021 |
4 | 231233210011 |
5 | 11032210201 |
6 | 1105003141 |
7 | 203632030 |
oct | 55574405 |
9 | 24505867 |
10 | 11991301 |
11 | 6850273 |
12 | 40234b1 |
13 | 263b05a |
14 | 1842017 |
15 | 10bcea1 |
hex | b6f905 |
11991301 has 4 divisors (see below), whose sum is σ = 13704352. Its totient is φ = 10278252.
The previous prime is 11991271. The next prime is 11991313. The reversal of 11991301 is 10319911.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11991301 - 25 = 11991269 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11991601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 856515 + ... + 856528.
It is an arithmetic number, because the mean of its divisors is an integer number (3426088).
Almost surely, 211991301 is an apocalyptic number.
It is an amenable number.
11991301 is a deficient number, since it is larger than the sum of its proper divisors (1713051).
11991301 is an equidigital number, since it uses as much as digits as its factorization.
11991301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1713050.
The product of its (nonzero) digits is 243, while the sum is 25.
The square root of 11991301 is about 3462.8457950073. The cubic root of 11991301 is about 228.8875136419.
It can be divided in two parts, 1199 and 1301, that added together give a square (2500 = 502).
The spelling of 11991301 in words is "eleven million, nine hundred ninety-one thousand, three hundred one".
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