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11992411 is a prime number
BaseRepresentation
bin101101101111…
…110101011011
3211120021111101
4231233311123
511032224121
61105012231
7203635204
oct55576533
924507441
1011992411
116851092
124024077
13263b702
1418425ab
1510bd491
hexb6fd5b

11992411 has 2 divisors, whose sum is σ = 11992412. Its totient is φ = 11992410.

The previous prime is 11992373. The next prime is 11992423. The reversal of 11992411 is 11429911.

It is a strong prime.

It is an emirp because it is prime and its reverse (11429911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11992411 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11992411.

It is not a weakly prime, because it can be changed into another prime (11992111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996205 + 5996206.

It is an arithmetic number, because the mean of its divisors is an integer number (5996206).

Almost surely, 211992411 is an apocalyptic number.

11992411 is a deficient number, since it is larger than the sum of its proper divisors (1).

11992411 is an equidigital number, since it uses as much as digits as its factorization.

11992411 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 28.

The square root of 11992411 is about 3463.0060641010. The cubic root of 11992411 is about 228.8945759087.

Subtracting from 11992411 its reverse (11429911), we obtain a square (562500 = 7502).

It can be divided in two parts, 11992 and 411, that added together give a triangular number (12403 = T157).

The spelling of 11992411 in words is "eleven million, nine hundred ninety-two thousand, four hundred eleven".