Base | Representation |
---|---|
bin | 101101101111… |
… | …111011011001 |
3 | 211120022000112 |
4 | 231233323121 |
5 | 11032232133 |
6 | 1105014105 |
7 | 203636261 |
oct | 55577331 |
9 | 24508015 |
10 | 11992793 |
11 | 68513aa |
12 | 4024335 |
13 | 263b937 |
14 | 18427a1 |
15 | 10bd648 |
hex | b6fed9 |
11992793 has 2 divisors, whose sum is σ = 11992794. Its totient is φ = 11992792.
The previous prime is 11992741. The next prime is 11992811. The reversal of 11992793 is 39729911.
11992793 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7139584 + 4853209 = 2672^2 + 2203^2 .
It is a cyclic number.
It is not a de Polignac number, because 11992793 - 214 = 11976409 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11992793.
It is not a weakly prime, because it can be changed into another prime (11992703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5996396 + 5996397.
It is an arithmetic number, because the mean of its divisors is an integer number (5996397).
Almost surely, 211992793 is an apocalyptic number.
It is an amenable number.
11992793 is a deficient number, since it is larger than the sum of its proper divisors (1).
11992793 is an equidigital number, since it uses as much as digits as its factorization.
11992793 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 30618, while the sum is 41.
The square root of 11992793 is about 3463.0612180555. The cubic root of 11992793 is about 228.8970062457.
The spelling of 11992793 in words is "eleven million, nine hundred ninety-two thousand, seven hundred ninety-three".
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