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11994803 is a prime number
BaseRepresentation
bin101101110000…
…011010110011
3211120101202222
4231300122303
511032313203
61105031255
7203645162
oct55603263
924511688
1011994803
116852967
12402552b
13263c822
1418433d9
1510be038
hexb706b3

11994803 has 2 divisors, whose sum is σ = 11994804. Its totient is φ = 11994802.

The previous prime is 11994793. The next prime is 11994839. The reversal of 11994803 is 30849911.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11994803 - 28 = 11994547 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11994863) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5997401 + 5997402.

It is an arithmetic number, because the mean of its divisors is an integer number (5997402).

Almost surely, 211994803 is an apocalyptic number.

11994803 is a deficient number, since it is larger than the sum of its proper divisors (1).

11994803 is an equidigital number, since it uses as much as digits as its factorization.

11994803 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 35.

The square root of 11994803 is about 3463.3514115665. The cubic root of 11994803 is about 228.9097932943.

The spelling of 11994803 in words is "eleven million, nine hundred ninety-four thousand, eight hundred three".