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11997513313 is a prime number
BaseRepresentation
bin10110010110001101…
…11000011001100001
31010222010102211020221
423023012320121201
5144032330411223
65302300203041
7603211115632
oct131306703141
933863384227
1011997513313
1150a7313365
1223a9b39481
1311927a3a06
1481b571889
154a342db5d
hex2cb1b8661

11997513313 has 2 divisors, whose sum is σ = 11997513314. Its totient is φ = 11997513312.

The previous prime is 11997513271. The next prime is 11997513347. The reversal of 11997513313 is 31331579911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8152645264 + 3844868049 = 90292^2 + 62007^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11997513313 is a prime.

It is a super-2 number, since 2×119975133132 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11997513313.

It is not a weakly prime, because it can be changed into another prime (11997513413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5998756656 + 5998756657.

It is an arithmetic number, because the mean of its divisors is an integer number (5998756657).

Almost surely, 211997513313 is an apocalyptic number.

It is an amenable number.

11997513313 is a deficient number, since it is larger than the sum of its proper divisors (1).

11997513313 is an equidigital number, since it uses as much as digits as its factorization.

11997513313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 76545, while the sum is 43.

The spelling of 11997513313 in words is "eleven billion, nine hundred ninety-seven million, five hundred thirteen thousand, three hundred thirteen".