119990753 has 2 divisors, whose sum is σ = 119990754. Its totient is φ = 119990752.

The previous prime is 119990729. The next prime is 119990771. The reversal of 119990753 is 357099911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107081104 + 12909649 = 10348^2 + 3593^2 .

It is a cyclic number.

It is not a de Polignac number, because 119990753 - 2¹⁰ = 119989729 is a prime.

It is a super-3 number, since 3×119990753³ (a number of 25 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (119990053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59995376 + 59995377.

It is an arithmetic number, because the mean of its divisors is an integer number (59995377).

Almost surely, 2^119990753 is an apocalyptic number.

It is an amenable number.

119990753 is a deficient number, since it is larger than the sum of its proper divisors (1).

119990753 is an equidigital number, since it uses as much as digits as its factorization.

119990753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76545, while the sum is 44.

The square root of 119990753 is about 10954.0290760980. The cubic root of 119990753 is about 493.2297450612.

The spelling of 119990753 in words is "one hundred nineteen million, nine hundred ninety thousand, seven hundred fifty-three".