Search a number
-
+
119995823252089 is a prime number
BaseRepresentation
bin11011010010001010110100…
…011010110110001001111001
3120201212111012020111020221101
4123102022310122312021321
5111212002421223031324
61103113153054411401
734163261235335431
oct3322126432661171
9521774166436841
10119995823252089
1135263a40a39734
121155bbb2500b61
1351c57330026c5
14218bb8646b2c1
15dd1577b1a944
hex6d22b46b6279

119995823252089 has 2 divisors, whose sum is σ = 119995823252090. Its totient is φ = 119995823252088.

The previous prime is 119995823252077. The next prime is 119995823252119. The reversal of 119995823252089 is 980252328599911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80244563632489 + 39751259619600 = 8957933^2 + 6304860^2 .

It is a cyclic number.

It is not a de Polignac number, because 119995823252089 - 213 = 119995823243897 is a prime.

It is a super-2 number, since 2×1199958232520892 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (119995823252009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59997911626044 + 59997911626045.

It is an arithmetic number, because the mean of its divisors is an integer number (59997911626045).

Almost surely, 2119995823252089 is an apocalyptic number.

It is an amenable number.

119995823252089 is a deficient number, since it is larger than the sum of its proper divisors (1).

119995823252089 is an equidigital number, since it uses as much as digits as its factorization.

119995823252089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 251942400, while the sum is 73.

The spelling of 119995823252089 in words is "one hundred nineteen trillion, nine hundred ninety-five billion, eight hundred twenty-three million, two hundred fifty-two thousand, eighty-nine".