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1200011011022 = 2600005505511
BaseRepresentation
bin10001011101100110001…
…110101110001111001110
311020201102211102112021002
4101131212032232033032
5124130110304323042
62315135532340302
7152461251203105
oct21354616561716
94221384375232
101200011011022
11422a15a2790a
121746a1314692
13892119717c5
144211bb9303c
1521335b63132
hex117663ae3ce

1200011011022 has 4 divisors (see below), whose sum is σ = 1800016516536. Its totient is φ = 600005505510.

The previous prime is 1200011010977. The next prime is 1200011011027. The reversal of 1200011011022 is 2201101100021.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1200011010994 and 1200011011012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200011011027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300002752754 + ... + 300002752757.

It is an arithmetic number, because the mean of its divisors is an integer number (450004129134).

Almost surely, 21200011011022 is an apocalyptic number.

1200011011022 is a deficient number, since it is larger than the sum of its proper divisors (600005505514).

1200011011022 is an equidigital number, since it uses as much as digits as its factorization.

1200011011022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600005505513.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 1200011011022 its reverse (2201101100021), we get a palindrome (3401112111043).

The spelling of 1200011011022 in words is "one trillion, two hundred billion, eleven million, eleven thousand, twenty-two".

Divisors: 1 2 600005505511 1200011011022