12000112200103 has 4 divisors (see below), whose sum is σ = 12631697052760. Its totient is φ = 11368527347448.

The previous prime is 12000112200079. The next prime is 12000112200107. The reversal of 12000112200103 is 30100221100021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12000112200103 - 2²⁹ = 11999575329191 is a prime.

It is a super-2 number, since 2×12000112200103² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000112200107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315792426300 + ... + 315792426337.

It is an arithmetic number, because the mean of its divisors is an integer number (3157924263190).

Almost surely, 2^{12000112200103} is an apocalyptic number.

12000112200103 is a deficient number, since it is larger than the sum of its proper divisors (631584852657).

12000112200103 is an equidigital number, since it uses as much as digits as its factorization.

12000112200103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 631584852656.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12000112200103 its reverse (30100221100021), we get a palindrome (42100333300124).

The spelling of 12000112200103 in words is "twelve trillion, one hundred twelve million, two hundred thousand, one hundred three".