Base | Representation |
---|---|
bin | 11011010010001111110000… |
… | …010000000010111001100011 |
3 | 120201212222212112001121100102 |
4 | 123102033300100002321203 |
5 | 111212044244214132323 |
6 | 1103115430541413015 |
7 | 34163536446204251 |
oct | 3322176020027143 |
9 | 521788775047312 |
10 | 120001122020963 |
11 | 3526620aa5a167 |
12 | 11561030b6a16b |
13 | 51c6098a1a8c1 |
14 | 218c12a0a15d1 |
15 | dd1787ddb328 |
hex | 6d23f0402e63 |
120001122020963 has 2 divisors, whose sum is σ = 120001122020964. Its totient is φ = 120001122020962.
The previous prime is 120001122020869. The next prime is 120001122021031. The reversal of 120001122020963 is 369020221100021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120001122020963 - 28 = 120001122020707 is a prime.
It is a super-2 number, since 2×1200011220209632 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120001122022963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000561010481 + 60000561010482.
It is an arithmetic number, because the mean of its divisors is an integer number (60000561010482).
Almost surely, 2120001122020963 is an apocalyptic number.
120001122020963 is a deficient number, since it is larger than the sum of its proper divisors (1).
120001122020963 is an equidigital number, since it uses as much as digits as its factorization.
120001122020963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 120001122020963 its reverse (369020221100021), we get a palindrome (489021343120984).
The spelling of 120001122020963 in words is "one hundred twenty trillion, one billion, one hundred twenty-two million, twenty thousand, nine hundred sixty-three".
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