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120001211110200 = 233527191421355321
BaseRepresentation
bin11011010010001111110101…
…100011111001001100111000
3120201220000002201200210210210
4123102033311203321030320
5111212044440021011300
61103115443443111120
734163541610354530
oct3322176543711470
9521800081623723
10120001211110200
1135266256279232
12115610569724a0
1351c60b1311124
14218c137c524c0
15dd1790b38050
hex6d23f58f9338

120001211110200 has 384 divisors, whose sum is σ = 428389392752640. Its totient is φ = 27220354560000.

The previous prime is 120001211110181. The next prime is 120001211110219. The reversal of 120001211110200 is 2011112100021.

It is an interprime number because it is at equal distance from previous prime (120001211110181) and next prime (120001211110219).

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 337548540 + ... + 337903860.

It is an arithmetic number, because the mean of its divisors is an integer number (1115597376960).

Almost surely, 2120001211110200 is an apocalyptic number.

120001211110200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120001211110200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (214194696376320).

120001211110200 is an abundant number, since it is smaller than the sum of its proper divisors (308388181642440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120001211110200 is a wasteful number, since it uses less digits than its factorization.

120001211110200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 355959 (or 355950 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 12.

Adding to 120001211110200 its reverse (2011112100021), we get a palindrome (122012323210221).

The spelling of 120001211110200 in words is "one hundred twenty trillion, one billion, two hundred eleven million, one hundred ten thousand, two hundred".