Base | Representation |
---|---|
bin | 11011010010001111111011… |
… | …011101111110010000010010 |
3 | 120201220000100122012011201101 |
4 | 123102033323131332100102 |
5 | 111212100140404040310 |
6 | 1103115501343255014 |
7 | 34163544222655336 |
oct | 3322177335762022 |
9 | 521800318164641 |
10 | 120001310221330 |
11 | 352662a721295a |
12 | 11561083baa46a |
13 | 51c60c8a03175 |
14 | 218c1470917c6 |
15 | dd17996b443a |
hex | 6d23fb77e412 |
120001310221330 has 8 divisors (see below), whose sum is σ = 216002358398412. Its totient is φ = 48000524088528.
The previous prime is 120001310221321. The next prime is 120001310221391. The reversal of 120001310221330 is 33122013100021.
It can be written as a sum of positive squares in 2 ways, for example, as 98377852310721 + 21623457910609 = 9918561^2 + 4650103^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 120001310221298 and 120001310221307.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6000065511057 + ... + 6000065511076.
Almost surely, 2120001310221330 is an apocalyptic number.
120001310221330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120001310221330 is a deficient number, since it is larger than the sum of its proper divisors (96001048177082).
120001310221330 is a wasteful number, since it uses less digits than its factorization.
120001310221330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12000131022140.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 120001310221330 its reverse (33122013100021), we get a palindrome (153123323321351).
The spelling of 120001310221330 in words is "one hundred twenty trillion, one billion, three hundred ten million, two hundred twenty-one thousand, three hundred thirty".
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