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120001321014 = 2320000220169
BaseRepresentation
bin110111111000010100…
…0101101100000110110
3102110202002122201120220
41233300220231200312
53431230314233024
6131043340435210
711445513253521
oct1576050554066
9373662581526
10120001321014
114698a687673
121b310248b06
13b41555a733
145b455abbb8
1531c5166e79
hex1bf0a2d836

120001321014 has 8 divisors (see below), whose sum is σ = 240002642040. Its totient is φ = 40000440336.

The previous prime is 120001320983. The next prime is 120001321051. The reversal of 120001321014 is 410123100021.

It is a sphenic number, since it is the product of 3 distinct primes.

120001321014 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 120001320984 and 120001321002.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10000110079 + ... + 10000110090.

It is an arithmetic number, because the mean of its divisors is an integer number (30000330255).

Almost surely, 2120001321014 is an apocalyptic number.

120001321014 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120001321014 is a wasteful number, since it uses less digits than its factorization.

120001321014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20000220174.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 120001321014 its reverse (410123100021), we get a palindrome (530124421035).

The spelling of 120001321014 in words is "one hundred twenty billion, one million, three hundred twenty-one thousand, fourteen".

Divisors: 1 2 3 6 20000220169 40000440338 60000660507 120001321014