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12000151535 = 52400030307
BaseRepresentation
bin10110010110100001…
…11100011111101111
31010222022101212012212
423023100330133233
5144034014322120
65302432521035
7603242414351
oct131320743757
933868355185
1012000151535
1150a8855509
1223aa9b017b
1311931b87a8
1481ba5b0d1
154a37a06c5
hex2cb43c7ef

12000151535 has 4 divisors (see below), whose sum is σ = 14400181848. Its totient is φ = 9600121224.

The previous prime is 12000151489. The next prime is 12000151589. The reversal of 12000151535 is 53515100021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12000151535 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12000151535.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1200015149 + ... + 1200015158.

It is an arithmetic number, because the mean of its divisors is an integer number (3600045462).

Almost surely, 212000151535 is an apocalyptic number.

12000151535 is a deficient number, since it is larger than the sum of its proper divisors (2400030313).

12000151535 is an equidigital number, since it uses as much as digits as its factorization.

12000151535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2400030312.

The product of its (nonzero) digits is 750, while the sum is 23.

Adding to 12000151535 its reverse (53515100021), we get a palindrome (65515251556).

The spelling of 12000151535 in words is "twelve billion, one hundred fifty-one thousand, five hundred thirty-five".

Divisors: 1 5 2400030307 12000151535