Base | Representation |
---|---|
bin | 11011010010010000100100… |
… | …100110000110111110001011 |
3 | 120201220002010201112202000021 |
4 | 123102100210212012332023 |
5 | 111212103044024020133 |
6 | 1103120054032321311 |
7 | 34163600301603364 |
oct | 3322204446067613 |
9 | 521802121482007 |
10 | 120002000220043 |
11 | 35266620751127 |
12 | 115612370a3237 |
13 | 51c61a8950226 |
14 | 218c1b0984b6b |
15 | dd17da05d52d |
hex | 6d2424986f8b |
120002000220043 has 2 divisors, whose sum is σ = 120002000220044. Its totient is φ = 120002000220042.
The previous prime is 120002000220029. The next prime is 120002000220121. The reversal of 120002000220043 is 340022000200021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120002000220043 is a prime.
It is a super-2 number, since 2×1200020002200432 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120002000219999 and 120002000220026.
It is not a weakly prime, because it can be changed into another prime (120002000220643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001000110021 + 60001000110022.
It is an arithmetic number, because the mean of its divisors is an integer number (60001000110022).
Almost surely, 2120002000220043 is an apocalyptic number.
120002000220043 is a deficient number, since it is larger than the sum of its proper divisors (1).
120002000220043 is an equidigital number, since it uses as much as digits as its factorization.
120002000220043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 16.
Adding to 120002000220043 its reverse (340022000200021), we get a palindrome (460024000420064).
The spelling of 120002000220043 in words is "one hundred twenty trillion, two billion, two hundred twenty thousand, forty-three".
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