Base | Representation |
---|---|
bin | 11011010010010000100101… |
… | …011000000111101110010011 |
3 | 120201220002011122012210221012 |
4 | 123102100211120013232103 |
5 | 111212103110403032243 |
6 | 1103120055221321135 |
7 | 34163600521205645 |
oct | 3322204530075623 |
9 | 521802148183835 |
10 | 120002013330323 |
11 | 35266628096073 |
12 | 1156123b5661ab |
13 | 51c61ab5906a7 |
14 | 218c1b25d8895 |
15 | dd17db29cd18 |
hex | 6d2425607b93 |
120002013330323 has 2 divisors, whose sum is σ = 120002013330324. Its totient is φ = 120002013330322.
The previous prime is 120002013330289. The next prime is 120002013330443. The reversal of 120002013330323 is 323033310200021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120002013330323 - 216 = 120002013264787 is a prime.
It is a super-2 number, since 2×1200020133303232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120002013330223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001006665161 + 60001006665162.
It is an arithmetic number, because the mean of its divisors is an integer number (60001006665162).
Almost surely, 2120002013330323 is an apocalyptic number.
120002013330323 is a deficient number, since it is larger than the sum of its proper divisors (1).
120002013330323 is an equidigital number, since it uses as much as digits as its factorization.
120002013330323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 120002013330323 its reverse (323033310200021), we get a palindrome (443035323530344).
The spelling of 120002013330323 in words is "one hundred twenty trillion, two billion, thirteen million, three hundred thirty thousand, three hundred twenty-three".
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