Search a number
-
+
120002212222121 is a prime number
BaseRepresentation
bin11011010010010000110001…
…001110110101010010101001
3120201220002200111110120012002
4123102100301032311102221
5111212104012312101441
61103120131044300345
734163605454566265
oct3322206116652251
9521802614416162
10120002212222121
113526671a391459
12115612960a16b5
1351c621084a448
14218c1d0bad0a5
15dd17ed988b9b
hex6d24313b54a9

120002212222121 has 2 divisors, whose sum is σ = 120002212222122. Its totient is φ = 120002212222120.

The previous prime is 120002212222063. The next prime is 120002212222157. The reversal of 120002212222121 is 121222212200021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 98144904189721 + 21857308032400 = 9906811^2 + 4675180^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120002212222121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120002212222093 and 120002212222102.

It is not a weakly prime, because it can be changed into another prime (120002212222021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001106111060 + 60001106111061.

It is an arithmetic number, because the mean of its divisors is an integer number (60001106111061).

Almost surely, 2120002212222121 is an apocalyptic number.

It is an amenable number.

120002212222121 is a deficient number, since it is larger than the sum of its proper divisors (1).

120002212222121 is an equidigital number, since it uses as much as digits as its factorization.

120002212222121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 20.

Adding to 120002212222121 its reverse (121222212200021), we get a palindrome (241224424422142).

The spelling of 120002212222121 in words is "one hundred twenty trillion, two billion, two hundred twelve million, two hundred twenty-two thousand, one hundred twenty-one".