Base | Representation |
---|---|
bin | 10001011101100110111… |
… | …010010100110111101011 |
3 | 11020201110121221020212022 |
4 | 101131212322110313223 |
5 | 124130121221111301 |
6 | 2315141021335055 |
7 | 152461450311011 |
oct | 21354672246753 |
9 | 4221417836768 |
10 | 1200022441451 |
11 | 422a21424749 |
12 | 1746a510748b |
13 | 89214144482 |
14 | 4211d4ca8b1 |
15 | 21336b6ed1b |
hex | 11766e94deb |
1200022441451 has 2 divisors, whose sum is σ = 1200022441452. Its totient is φ = 1200022441450.
The previous prime is 1200022441393. The next prime is 1200022441459. The reversal of 1200022441451 is 1541442200021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1200022441451 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1200022441451.
It is not a weakly prime, because it can be changed into another prime (1200022441459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600011220725 + 600011220726.
It is an arithmetic number, because the mean of its divisors is an integer number (600011220726).
Almost surely, 21200022441451 is an apocalyptic number.
1200022441451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200022441451 is an equidigital number, since it uses as much as digits as its factorization.
1200022441451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2560, while the sum is 26.
Adding to 1200022441451 its reverse (1541442200021), we get a palindrome (2741464641472).
The spelling of 1200022441451 in words is "one trillion, two hundred billion, twenty-two million, four hundred forty-one thousand, four hundred fifty-one".
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