Base | Representation |
---|---|
bin | 10110010110100010… |
… | …10000001010101111 |
3 | 1010222022112221202011 |
4 | 23023101100022233 |
5 | 144034024411421 |
6 | 5302434342051 |
7 | 603243201310 |
oct | 131321201257 |
9 | 33868487664 |
10 | 12000232111 |
11 | 50a88aaaaa |
12 | 23aaa2a927 |
13 | 119321637a |
14 | 81ba7c607 |
15 | 4a37b94e1 |
hex | 2cb4502af |
12000232111 has 4 divisors (see below), whose sum is σ = 13714550992. Its totient is φ = 10285913232.
The previous prime is 12000232099. The next prime is 12000232169. The reversal of 12000232111 is 11123200021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11123200021 = 2741 ⋅4058081.
It is not a de Polignac number, because 12000232111 - 29 = 12000231599 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12000232091 and 12000232100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12000232511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857159430 + ... + 857159443.
It is an arithmetic number, because the mean of its divisors is an integer number (3428637748).
Almost surely, 212000232111 is an apocalyptic number.
12000232111 is a deficient number, since it is larger than the sum of its proper divisors (1714318881).
12000232111 is an equidigital number, since it uses as much as digits as its factorization.
12000232111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1714318880.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 12000232111 its reverse (11123200021), we get a palindrome (23123432132).
The spelling of 12000232111 in words is "twelve billion, two hundred thirty-two thousand, one hundred eleven".
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