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12000243311 = 74001428473
BaseRepresentation
bin10110010110100010…
…10010111001101111
31010222022120112002222
423023101102321233
5144034030241221
65302434505555
7603243246050
oct131321227157
933868515088
1012000243311
1150a8908461
1223aaa352bb
13119321b4b4
1481ba82727
154a37bc9ab
hex2cb452e6f

12000243311 has 8 divisors (see below), whose sum is σ = 13718023584. Its totient is φ = 10283328000.

The previous prime is 12000243293. The next prime is 12000243317. The reversal of 12000243311 is 11334200021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12000243311 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12000243311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000243317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 186230 + ... + 242243.

It is an arithmetic number, because the mean of its divisors is an integer number (1714752948).

Almost surely, 212000243311 is an apocalyptic number.

12000243311 is a deficient number, since it is larger than the sum of its proper divisors (1717780273).

12000243311 is an equidigital number, since it uses as much as digits as its factorization.

12000243311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 432481.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12000243311 its reverse (11334200021), we get a palindrome (23334443332).

The spelling of 12000243311 in words is "twelve billion, two hundred forty-three thousand, three hundred eleven".

Divisors: 1 7 4001 28007 428473 2999311 1714320473 12000243311