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12000250313 is a prime number
BaseRepresentation
bin10110010110100010…
…10100100111001001
31010222022120212201022
423023101110213021
5144034031002223
65302435002225
7603243305342
oct131321244711
933868525638
1012000250313
1150a8912747
1223aaa39375
13119322173c
1481ba850c9
154a37beac8
hex2cb4549c9

12000250313 has 2 divisors, whose sum is σ = 12000250314. Its totient is φ = 12000250312.

The previous prime is 12000250291. The next prime is 12000250321. The reversal of 12000250313 is 31305200021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7064906809 + 4935343504 = 84053^2 + 70252^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000250313 - 212 = 12000246217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12000250291 and 12000250300.

It is not a weakly prime, because it can be changed into another prime (12000250333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000125156 + 6000125157.

It is an arithmetic number, because the mean of its divisors is an integer number (6000125157).

Almost surely, 212000250313 is an apocalyptic number.

It is an amenable number.

12000250313 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000250313 is an equidigital number, since it uses as much as digits as its factorization.

12000250313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 17.

Adding to 12000250313 its reverse (31305200021), we get a palindrome (43305450334).

The spelling of 12000250313 in words is "twelve billion, two hundred fifty thousand, three hundred thirteen".