Base | Representation |
---|---|
bin | 10001011101100111100… |
… | …011000011111101101011 |
3 | 11020201111101000210020002 |
4 | 101131213203003331223 |
5 | 124130131434320412 |
6 | 2315142042253215 |
7 | 152461640135063 |
oct | 21354743037553 |
9 | 4221441023202 |
10 | 1200033120107 |
11 | 422a27458788 |
12 | 1746a87b720b |
13 | 89216412bc3 |
14 | 42120aaa3a3 |
15 | 21337a7ddc2 |
hex | 117678c3f6b |
1200033120107 has 2 divisors, whose sum is σ = 1200033120108. Its totient is φ = 1200033120106.
The previous prime is 1200033120089. The next prime is 1200033120113. The reversal of 1200033120107 is 7010213300021.
It is a strong prime.
It is an emirp because it is prime and its reverse (7010213300021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1200033120107 - 214 = 1200033103723 is a prime.
It is not a weakly prime, because it can be changed into another prime (1200033120007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600016560053 + 600016560054.
It is an arithmetic number, because the mean of its divisors is an integer number (600016560054).
Almost surely, 21200033120107 is an apocalyptic number.
1200033120107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200033120107 is an equidigital number, since it uses as much as digits as its factorization.
1200033120107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 20.
Adding to 1200033120107 its reverse (7010213300021), we get a palindrome (8210246420128).
The spelling of 1200033120107 in words is "one trillion, two hundred billion, thirty-three million, one hundred twenty thousand, one hundred seven".
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