1200034234141 has 4 divisors (see below), whose sum is σ = 1227942007072. Its totient is φ = 1172126461212.

The previous prime is 1200034234111. The next prime is 1200034234151. The reversal of 1200034234141 is 1414324300021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1200034234141 is a prime.

It is a super-2 number, since 2×1200034234141² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200034234111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13953886401 + ... + 13953886486.

It is an arithmetic number, because the mean of its divisors is an integer number (306985501768).

Almost surely, 2^{1200034234141} is an apocalyptic number.

It is an amenable number.

1200034234141 is a deficient number, since it is larger than the sum of its proper divisors (27907772931).

1200034234141 is an equidigital number, since it uses as much as digits as its factorization.

1200034234141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27907772930.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1200034234141 its reverse (1414324300021), we get a palindrome (2614358534162).

The spelling of 1200034234141 in words is "one trillion, two hundred billion, thirty-four million, two hundred thirty-four thousand, one hundred forty-one".