12000404013 has 8 divisors (see below), whose sum is σ = 17231349408. Its totient is φ = 7384863984.

The previous prime is 12000404011. The next prime is 12000404041. The reversal of 12000404013 is 31040400021.

12000404013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12000404013 - 2¹ = 12000404011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12000403983 and 12000404001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000404011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 153851295 + ... + 153851372.

It is an arithmetic number, because the mean of its divisors is an integer number (2153918676).

Almost surely, 2^12000404013 is an apocalyptic number.

12000404013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12000404013 is a deficient number, since it is larger than the sum of its proper divisors (5230945395).

12000404013 is a wasteful number, since it uses less digits than its factorization.

12000404013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 307702683.

The product of its (nonzero) digits is 96, while the sum is 15.

Adding to 12000404013 its reverse (31040400021), we get a palindrome (43040804034).

The spelling of 12000404013 in words is "twelve billion, four hundred four thousand, thirteen".