Base | Representation |
---|---|
bin | 110111111000011001… |
… | …1010110011110101011 |
3 | 102110202021220102200222 |
4 | 1233300303112132223 |
5 | 3431232023012001 |
6 | 131043520320255 |
7 | 11445546051434 |
oct | 1576063263653 |
9 | 373667812628 |
10 | 120004110251 |
11 | 46991212223 |
12 | 1b31117308b |
13 | b415cc617c |
14 | 5b45ad648b |
15 | 31c551861b |
hex | 1bf0cd67ab |
120004110251 has 2 divisors, whose sum is σ = 120004110252. Its totient is φ = 120004110250.
The previous prime is 120004110211. The next prime is 120004110283. The reversal of 120004110251 is 152011400021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120004110251 is a prime.
It is not a weakly prime, because it can be changed into another prime (120004110211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60002055125 + 60002055126.
It is an arithmetic number, because the mean of its divisors is an integer number (60002055126).
Almost surely, 2120004110251 is an apocalyptic number.
120004110251 is a deficient number, since it is larger than the sum of its proper divisors (1).
120004110251 is an equidigital number, since it uses as much as digits as its factorization.
120004110251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 120004110251 its reverse (152011400021), we get a palindrome (272015510272).
The spelling of 120004110251 in words is "one hundred twenty billion, four million, one hundred ten thousand, two hundred fifty-one".
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