1200054993457 has 2 divisors, whose sum is σ = 1200054993458. Its totient is φ = 1200054993456.

The previous prime is 1200054993301. The next prime is 1200054993481. The reversal of 1200054993457 is 7543994500021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 969927552801 + 230127440656 = 984849^2 + 479716^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200054993457 - 2¹¹ = 1200054991409 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1200054993457.

It is not a weakly prime, because it can be changed into another prime (1200054903457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600027496728 + 600027496729.

It is an arithmetic number, because the mean of its divisors is an integer number (600027496729).

Almost surely, 2^{1200054993457} is an apocalyptic number.

It is an amenable number.

1200054993457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200054993457 is an equidigital number, since it uses as much as digits as its factorization.

1200054993457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 49.

The spelling of 1200054993457 in words is "one trillion, two hundred billion, fifty-four million, nine hundred ninety-three thousand, four hundred fifty-seven".