Base | Representation |
---|---|
bin | 10110010110101000… |
… | …01110000100101011 |
3 | 1010222101000110202111 |
4 | 23023110032010223 |
5 | 144034224304323 |
6 | 5302503143151 |
7 | 603252621145 |
oct | 131324160453 |
9 | 33871013674 |
10 | 12001009963 |
11 | 50a9291458 |
12 | 23ab144ab7 |
13 | 1193429437 |
14 | 81bc01c95 |
15 | 4a38bec0d |
hex | 2cb50e12b |
12001009963 has 2 divisors, whose sum is σ = 12001009964. Its totient is φ = 12001009962.
The previous prime is 12001009949. The next prime is 12001010029. The reversal of 12001009963 is 36990010021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12001009963 - 25 = 12001009931 is a prime.
It is a super-2 number, since 2×120010099632 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12001009663) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000504981 + 6000504982.
It is an arithmetic number, because the mean of its divisors is an integer number (6000504982).
Almost surely, 212001009963 is an apocalyptic number.
12001009963 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001009963 is an equidigital number, since it uses as much as digits as its factorization.
12001009963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 31.
Adding to 12001009963 its reverse (36990010021), we get a palindrome (48991019984).
The spelling of 12001009963 in words is "twelve billion, one million, nine thousand, nine hundred sixty-three".
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