Base | Representation |
---|---|
bin | 10001011101101011101… |
… | …011000100111100000001 |
3 | 11020201200012021000111122 |
4 | 101131223223010330001 |
5 | 124130302144030423 |
6 | 2315152553522025 |
7 | 152463440331401 |
oct | 21355353047401 |
9 | 4221605230448 |
10 | 1200102330113 |
11 | 422a6252a235 |
12 | 174707a13315 |
13 | 89227865c7b |
14 | 42129d64801 |
15 | 2133dba08c8 |
hex | 1176bac4f01 |
1200102330113 has 2 divisors, whose sum is σ = 1200102330114. Its totient is φ = 1200102330112.
The previous prime is 1200102330083. The next prime is 1200102330173. The reversal of 1200102330113 is 3110332010021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 651165074704 + 548937255409 = 806948^2 + 740903^2 .
It is a cyclic number.
It is not a de Polignac number, because 1200102330113 - 210 = 1200102329089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1200102330091 and 1200102330100.
It is not a weakly prime, because it can be changed into another prime (1200102330173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600051165056 + 600051165057.
It is an arithmetic number, because the mean of its divisors is an integer number (600051165057).
Almost surely, 21200102330113 is an apocalyptic number.
It is an amenable number.
1200102330113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1200102330113 is an equidigital number, since it uses as much as digits as its factorization.
1200102330113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1200102330113 its reverse (3110332010021), we get a palindrome (4310434340134).
The spelling of 1200102330113 in words is "one trillion, two hundred billion, one hundred two million, three hundred thirty thousand, one hundred thirteen".
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