Base | Representation |
---|---|
bin | 1010111010100011100101… |
… | …1011010111011000001011 |
3 | 1120111021221102212120202012 |
4 | 2232220321123113120023 |
5 | 3033111224114144404 |
6 | 41305121415530135 |
7 | 2346023332502666 |
oct | 256507133273013 |
9 | 46437842776665 |
10 | 12001102099979 |
11 | 39077032a3933 |
12 | 1419a8898994b |
13 | 690911b27355 |
14 | 2d6bdc1066dd |
15 | 15c299a6da6e |
hex | aea396d760b |
12001102099979 has 2 divisors, whose sum is σ = 12001102099980. Its totient is φ = 12001102099978.
The previous prime is 12001102099957. The next prime is 12001102100011. The reversal of 12001102099979 is 97999020110021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12001102099979 - 212 = 12001102095883 is a prime.
It is a super-3 number, since 3×120011020999793 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (12001102099949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000551049989 + 6000551049990.
It is an arithmetic number, because the mean of its divisors is an integer number (6000551049990).
Almost surely, 212001102099979 is an apocalyptic number.
12001102099979 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001102099979 is an equidigital number, since it uses as much as digits as its factorization.
12001102099979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 183708, while the sum is 50.
The spelling of 12001102099979 in words is "twelve trillion, one billion, one hundred two million, ninety-nine thousand, nine hundred seventy-nine".
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