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1200111102251 is a prime number
BaseRepresentation
bin10001011101101100001…
…100100010100100101011
311020201200210202200121122
4101131230030202210223
5124130311420233001
62315153505525455
7152463605025215
oct21355414424453
94221623680548
101200111102251
11422a67480936
1217470a94388b
1389229617999
144212b1a95b5
152133e834b1b
hex1176c32292b

1200111102251 has 2 divisors, whose sum is σ = 1200111102252. Its totient is φ = 1200111102250.

The previous prime is 1200111102181. The next prime is 1200111102277. The reversal of 1200111102251 is 1522011110021.

It is a strong prime.

It is an emirp because it is prime and its reverse (1522011110021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200111102251 - 222 = 1200106907947 is a prime.

It is a super-2 number, since 2×12001111022512 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1200111102451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600055551125 + 600055551126.

It is an arithmetic number, because the mean of its divisors is an integer number (600055551126).

Almost surely, 21200111102251 is an apocalyptic number.

1200111102251 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200111102251 is an equidigital number, since it uses as much as digits as its factorization.

1200111102251 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 40, while the sum is 17.

Adding to 1200111102251 its reverse (1522011110021), we get a palindrome (2722122212272).

The spelling of 1200111102251 in words is "one trillion, two hundred billion, one hundred eleven million, one hundred two thousand, two hundred fifty-one".