Base | Representation |
---|---|
bin | 1010111010100011100111… |
… | …1101101111010110111110 |
3 | 1120111021222001211101200111 |
4 | 2232220321331233112332 |
5 | 3033111233421023402 |
6 | 41305122341020234 |
7 | 2346023502213331 |
oct | 256507175572676 |
9 | 46437861741614 |
10 | 12001111111102 |
11 | 3907708399043 |
12 | 1419a8b9b467a |
13 | 690913960a89 |
14 | 2d6bdd3b0618 |
15 | 15c29a74d9d7 |
hex | aea39f6f5be |
12001111111102 has 4 divisors (see below), whose sum is σ = 18001666666656. Its totient is φ = 6000555555550.
The previous prime is 12001111111079. The next prime is 12001111111103. The reversal of 12001111111102 is 20111111110021.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×120011111111023 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12001111111103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000277777774 + ... + 3000277777777.
It is an arithmetic number, because the mean of its divisors is an integer number (4500416666664).
Almost surely, 212001111111102 is an apocalyptic number.
12001111111102 is a deficient number, since it is larger than the sum of its proper divisors (6000555555554).
12001111111102 is an equidigital number, since it uses as much as digits as its factorization.
12001111111102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6000555555553.
The product of its (nonzero) digits is 4, while the sum is 13.
Adding to 12001111111102 its reverse (20111111110021), we get a palindrome (32112222221123).
The spelling of 12001111111102 in words is "twelve trillion, one billion, one hundred eleven million, one hundred eleven thousand, one hundred two".
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