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12001111200103 = 15773760864211
BaseRepresentation
bin1010111010100011100111…
…1110000101000101100111
31120111021222001222220202211
42232220321332011011213
53033111233431400403
641305122342544251
72346023503033654
oct256507176050547
946437861886684
1012001111200103
1139077084499a3
121419a8ba38087
1369091399243c
142d6bdd3d4c2b
1515c29a76a06d
hexaea39f85167

12001111200103 has 4 divisors (see below), whose sum is σ = 12001872080088. Its totient is φ = 12000350320120.

The previous prime is 12001111200019. The next prime is 12001111200151. The reversal of 12001111200103 is 30100211110021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12001111200103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12001111200173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380416333 + ... + 380447878.

It is an arithmetic number, because the mean of its divisors is an integer number (3000468020022).

Almost surely, 212001111200103 is an apocalyptic number.

12001111200103 is a deficient number, since it is larger than the sum of its proper divisors (760879985).

12001111200103 is an equidigital number, since it uses as much as digits as its factorization.

12001111200103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 760879984.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 12001111200103 its reverse (30100211110021), we get a palindrome (42101322310124).

The spelling of 12001111200103 in words is "twelve trillion, one billion, one hundred eleven million, two hundred thousand, one hundred three".

Divisors: 1 15773 760864211 12001111200103