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120011211133 = 1110910110103
BaseRepresentation
bin110111111000100111…
…0011100000101111101
3102110202210021012021121
41233301032130011331
53431240332224013
6131044332430541
711445663314632
oct1576116340575
9373683235247
10120011211133
1146995222220
121b313618451
13b417611288
145b46a24189
1531c5e6c58d
hex1bf139c17d

120011211133 has 4 divisors (see below), whose sum is σ = 130921321248. Its totient is φ = 109101101020.

The previous prime is 120011211097. The next prime is 120011211149. The reversal of 120011211133 is 331112110021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120011211133 - 217 = 120011080061 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120011211193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5455055041 + ... + 5455055062.

It is an arithmetic number, because the mean of its divisors is an integer number (32730330312).

Almost surely, 2120011211133 is an apocalyptic number.

It is an amenable number.

120011211133 is a deficient number, since it is larger than the sum of its proper divisors (10910110115).

120011211133 is a wasteful number, since it uses less digits than its factorization.

120011211133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10910110114.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 120011211133 its reverse (331112110021), we get a palindrome (451123321154).

The spelling of 120011211133 in words is "one hundred twenty billion, eleven million, two hundred eleven thousand, one hundred thirty-three".

Divisors: 1 11 10910110103 120011211133