Base | Representation |
---|---|
bin | 110111111000100111… |
… | …0110110101101101011 |
3 | 102110202210110201212001 |
4 | 1233301032312231223 |
5 | 3431240344221141 |
6 | 131044335031431 |
7 | 11445664250551 |
oct | 1576116665553 |
9 | 373683421761 |
10 | 120011320171 |
11 | 46995297136 |
12 | 1b31366b577 |
13 | b41764bab2 |
14 | 5b46a51bd1 |
15 | 31c5e8ea31 |
hex | 1bf13b6b6b |
120011320171 has 2 divisors, whose sum is σ = 120011320172. Its totient is φ = 120011320170.
The previous prime is 120011320147. The next prime is 120011320213. The reversal of 120011320171 is 171023110021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120011320171 - 25 = 120011320139 is a prime.
It is not a weakly prime, because it can be changed into another prime (120011350171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60005660085 + 60005660086.
It is an arithmetic number, because the mean of its divisors is an integer number (60005660086).
Almost surely, 2120011320171 is an apocalyptic number.
120011320171 is a deficient number, since it is larger than the sum of its proper divisors (1).
120011320171 is an equidigital number, since it uses as much as digits as its factorization.
120011320171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 120011320171 its reverse (171023110021), we get a palindrome (291034430192).
The spelling of 120011320171 in words is "one hundred twenty billion, eleven million, three hundred twenty thousand, one hundred seventy-one".
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