1200113240147 has 2 divisors, whose sum is σ = 1200113240148. Its totient is φ = 1200113240146.

The previous prime is 1200113240119. The next prime is 1200113240233. The reversal of 1200113240147 is 7410423110021.

It is a weak prime.

It is an emirp because it is prime and its reverse (7410423110021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1200113240147 - 2²⁰ = 1200112191571 is a prime.

It is a super-2 number, since 2×1200113240147² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1200113240947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600056620073 + 600056620074.

It is an arithmetic number, because the mean of its divisors is an integer number (600056620074).

Almost surely, 2^{1200113240147} is an apocalyptic number.

1200113240147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200113240147 is an equidigital number, since it uses as much as digits as its factorization.

1200113240147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 1200113240147 its reverse (7410423110021), we get a palindrome (8610536350168).

The spelling of 1200113240147 in words is "one trillion, two hundred billion, one hundred thirteen million, two hundred forty thousand, one hundred forty-seven".