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120012311031211 is a prime number
BaseRepresentation
bin11011010010011010001011…
…001010101110110110101011
3120201221001202022011012220101
4123102122023022232312223
5111212240203110444321
61103124521121010231
734164413642213344
oct3322321312566653
9521831668135811
10120012311031211
113526aa31954175
1211563234183977
1351c715cb52321
14218c8ac0d30cb
15dd1be0363791
hex6d268b2aedab

120012311031211 has 2 divisors, whose sum is σ = 120012311031212. Its totient is φ = 120012311031210.

The previous prime is 120012311031187. The next prime is 120012311031233. The reversal of 120012311031211 is 112130113210021.

It is a strong prime.

It is an emirp because it is prime and its reverse (112130113210021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120012311031211 - 213 = 120012311023019 is a prime.

It is a super-3 number, since 3×1200123110312113 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (120012311001211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006155515605 + 60006155515606.

It is an arithmetic number, because the mean of its divisors is an integer number (60006155515606).

Almost surely, 2120012311031211 is an apocalyptic number.

120012311031211 is a deficient number, since it is larger than the sum of its proper divisors (1).

120012311031211 is an equidigital number, since it uses as much as digits as its factorization.

120012311031211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 120012311031211 its reverse (112130113210021), we get a palindrome (232142424241232).

The spelling of 120012311031211 in words is "one hundred twenty trillion, twelve billion, three hundred eleven million, thirty-one thousand, two hundred eleven".