Base | Representation |
---|---|
bin | 1010111010100100010100… |
… | …1110010101010010001011 |
3 | 1120111022110020021110102112 |
4 | 2232221011032111102023 |
5 | 3033112130300310443 |
6 | 41305153205452535 |
7 | 2346031254634334 |
oct | 256510516252213 |
9 | 46438406243375 |
10 | 12001300010123 |
11 | 39077a4a89736 |
12 | 1419b2311114b |
13 | 690943b2c348 |
14 | 2d6c1a50328b |
15 | 15c2ac113b18 |
hex | aea4539548b |
12001300010123 has 2 divisors, whose sum is σ = 12001300010124. Its totient is φ = 12001300010122.
The previous prime is 12001300010111. The next prime is 12001300010131. The reversal of 12001300010123 is 32101000310021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12001300010123 - 224 = 12001283232907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12001300010098 and 12001300010107.
It is not a weakly prime, because it can be changed into another prime (12001300010723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000650005061 + 6000650005062.
It is an arithmetic number, because the mean of its divisors is an integer number (6000650005062).
Almost surely, 212001300010123 is an apocalyptic number.
12001300010123 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001300010123 is an equidigital number, since it uses as much as digits as its factorization.
12001300010123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 12001300010123 its reverse (32101000310021), we get a palindrome (44102300320144).
The spelling of 12001300010123 in words is "twelve trillion, one billion, three hundred million, ten thousand, one hundred twenty-three".
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