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1200131040111 = 31492684856913
BaseRepresentation
bin10001011101101101011…
…000100110001101101111
311020201202012021122012220
4101131231120212031233
5124130332021240421
62315155501130423
7152464236345123
oct21355530461557
94221665248186
101200131040111
11422a77759503
12174715559a13
13892307a8a33
144212dab9583
15213414723c6
hex1176d62636f

1200131040111 has 8 divisors (see below), whose sum is σ = 1610914148400. Its totient is φ = 794717645952.

The previous prime is 1200131040079. The next prime is 1200131040139. The reversal of 1200131040111 is 1110401310021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1200131040111 - 25 = 1200131040079 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200131040811) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1342428010 + ... + 1342428903.

It is an arithmetic number, because the mean of its divisors is an integer number (201364268550).

Almost surely, 21200131040111 is an apocalyptic number.

1200131040111 is a deficient number, since it is larger than the sum of its proper divisors (410783108289).

1200131040111 is a wasteful number, since it uses less digits than its factorization.

1200131040111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2684857065.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1200131040111 its reverse (1110401310021), we get a palindrome (2310532350132).

The spelling of 1200131040111 in words is "one trillion, two hundred billion, one hundred thirty-one million, forty thousand, one hundred eleven".

Divisors: 1 3 149 447 2684856913 8054570739 400043680037 1200131040111