Base | Representation |
---|---|
bin | 1010111010100100010111… |
… | …1001000110110101001001 |
3 | 1120111022111000101010202110 |
4 | 2232221011321012311021 |
5 | 3033112141133114423 |
6 | 41305154250052533 |
7 | 2346031452145302 |
oct | 256510571066511 |
9 | 46438430333673 |
10 | 12001311223113 |
11 | 3907800348173 |
12 | 1419b26a1a149 |
13 | 690946257054 |
14 | 2d6c1bbc17a9 |
15 | 15c2ad0cb193 |
hex | aea45e46d49 |
12001311223113 has 4 divisors (see below), whose sum is σ = 16001748297488. Its totient is φ = 8000874148740.
The previous prime is 12001311223079. The next prime is 12001311223207. The reversal of 12001311223113 is 31132211310021.
12001311223113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12001311223113 - 26 = 12001311223049 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 12001311223113.
It is not an unprimeable number, because it can be changed into a prime (12001311224113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000218537183 + ... + 2000218537188.
It is an arithmetic number, because the mean of its divisors is an integer number (4000437074372).
Almost surely, 212001311223113 is an apocalyptic number.
It is an amenable number.
12001311223113 is a deficient number, since it is larger than the sum of its proper divisors (4000437074375).
12001311223113 is an equidigital number, since it uses as much as digits as its factorization.
12001311223113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4000437074374.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12001311223113 its reverse (31132211310021), we get a palindrome (43133522533134).
The spelling of 12001311223113 in words is "twelve trillion, one billion, three hundred eleven million, two hundred twenty-three thousand, one hundred thirteen".
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