Base | Representation |
---|---|
bin | 1010111010100100010111… |
… | …1001000111000100110001 |
3 | 1120111022111000101012010111 |
4 | 2232221011321013010301 |
5 | 3033112141133132423 |
6 | 41305154250101321 |
7 | 2346031452151231 |
oct | 256510571070461 |
9 | 46438430335114 |
10 | 12001311224113 |
11 | 39078003489a2 |
12 | 1419b26a1a841 |
13 | 690946257643 |
14 | 2d6c1bbc1cc1 |
15 | 15c2ad0cb60d |
hex | aea45e47131 |
12001311224113 has 2 divisors, whose sum is σ = 12001311224114. Its totient is φ = 12001311224112.
The previous prime is 12001311224099. The next prime is 12001311224143. The reversal of 12001311224113 is 31142211310021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7549789345344 + 4451521878769 = 2747688^2 + 2109863^2 .
It is a cyclic number.
It is not a de Polignac number, because 12001311224113 - 213 = 12001311215921 is a prime.
It is not a weakly prime, because it can be changed into another prime (12001311224143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000655612056 + 6000655612057.
It is an arithmetic number, because the mean of its divisors is an integer number (6000655612057).
Almost surely, 212001311224113 is an apocalyptic number.
It is an amenable number.
12001311224113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001311224113 is an equidigital number, since it uses as much as digits as its factorization.
12001311224113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 12001311224113 its reverse (31142211310021), we get a palindrome (43143522534134).
The spelling of 12001311224113 in words is "twelve trillion, one billion, three hundred eleven million, two hundred twenty-four thousand, one hundred thirteen".
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