Base | Representation |
---|---|
bin | 1010111010100100010111… |
… | …1001000110110110100111 |
3 | 1120111022111000101010212221 |
4 | 2232221011321012312213 |
5 | 3033112141133120312 |
6 | 41305154250053211 |
7 | 2346031452145465 |
oct | 256510571066647 |
9 | 46438430333787 |
10 | 12001311223207 |
11 | 3907800348249 |
12 | 1419b26a1a207 |
13 | 6909462570c7 |
14 | 2d6c1bbc1835 |
15 | 15c2ad0cb207 |
hex | aea45e46da7 |
12001311223207 has 2 divisors, whose sum is σ = 12001311223208. Its totient is φ = 12001311223206.
The previous prime is 12001311223079. The next prime is 12001311223219. The reversal of 12001311223207 is 70232211310021.
It is a strong prime.
It is an emirp because it is prime and its reverse (70232211310021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12001311223207 - 27 = 12001311223079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12001311223607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000655611603 + 6000655611604.
It is an arithmetic number, because the mean of its divisors is an integer number (6000655611604).
Almost surely, 212001311223207 is an apocalyptic number.
12001311223207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001311223207 is an equidigital number, since it uses as much as digits as its factorization.
12001311223207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 12001311223207 its reverse (70232211310021), we get a palindrome (82233522533228).
The spelling of 12001311223207 in words is "twelve trillion, one billion, three hundred eleven million, two hundred twenty-three thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •