Base | Representation |
---|---|
bin | 1010111010100100010111… |
… | …1100011101011011100010 |
3 | 1120111022111002000210112001 |
4 | 2232221011330131123202 |
5 | 3033112141344231424 |
6 | 41305154320554214 |
7 | 2346031462466056 |
oct | 256510574353342 |
9 | 46438432023461 |
10 | 12001312102114 |
11 | 3907800898615 |
12 | 1419b2718296a |
13 | 6909464a417a |
14 | 2d6c1bd6dc66 |
15 | 15c2ad201844 |
hex | aea45f1d6e2 |
12001312102114 has 4 divisors (see below), whose sum is σ = 18001968153174. Its totient is φ = 6000656051056.
The previous prime is 12001312102111. The next prime is 12001312102151. The reversal of 12001312102114 is 41120121310021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9991396280889 + 2009915821225 = 3160917^2 + 1417715^2 .
It is a junction number, because it is equal to n+sod(n) for n = 12001312102091 and 12001312102100.
It is not an unprimeable number, because it can be changed into a prime (12001312102111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000328025527 + ... + 3000328025530.
Almost surely, 212001312102114 is an apocalyptic number.
12001312102114 is a deficient number, since it is larger than the sum of its proper divisors (6000656051060).
12001312102114 is an equidigital number, since it uses as much as digits as its factorization.
12001312102114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6000656051059.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 12001312102114 its reverse (41120121310021), we get a palindrome (53121433412135).
The spelling of 12001312102114 in words is "twelve trillion, one billion, three hundred twelve million, one hundred two thousand, one hundred fourteen".
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