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12001312102114 = 26000656051057
BaseRepresentation
bin1010111010100100010111…
…1100011101011011100010
31120111022111002000210112001
42232221011330131123202
53033112141344231424
641305154320554214
72346031462466056
oct256510574353342
946438432023461
1012001312102114
113907800898615
121419b2718296a
136909464a417a
142d6c1bd6dc66
1515c2ad201844
hexaea45f1d6e2

12001312102114 has 4 divisors (see below), whose sum is σ = 18001968153174. Its totient is φ = 6000656051056.

The previous prime is 12001312102111. The next prime is 12001312102151. The reversal of 12001312102114 is 41120121310021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9991396280889 + 2009915821225 = 3160917^2 + 1417715^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12001312102091 and 12001312102100.

It is not an unprimeable number, because it can be changed into a prime (12001312102111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000328025527 + ... + 3000328025530.

Almost surely, 212001312102114 is an apocalyptic number.

12001312102114 is a deficient number, since it is larger than the sum of its proper divisors (6000656051060).

12001312102114 is an equidigital number, since it uses as much as digits as its factorization.

12001312102114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6000656051059.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 12001312102114 its reverse (41120121310021), we get a palindrome (53121433412135).

The spelling of 12001312102114 in words is "twelve trillion, one billion, three hundred twelve million, one hundred two thousand, one hundred fourteen".

Divisors: 1 2 6000656051057 12001312102114