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1200132131147 is a prime number
BaseRepresentation
bin10001011101101101011…
…100110000100101001011
311020201202021100001211122
4101131231130300211023
5124130332311144042
62315155540345455
7152464251541025
oct21355534604513
94221667301748
101200132131147
11422a78334194
121747159a528b
1389230a9b511
144212dcc1015
15213415da7d2
hex1176d73094b

1200132131147 has 2 divisors, whose sum is σ = 1200132131148. Its totient is φ = 1200132131146.

The previous prime is 1200132131063. The next prime is 1200132131153. The reversal of 1200132131147 is 7411312310021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1200132131147 - 28 = 1200132130891 is a prime.

It is a super-2 number, since 2×12001321311472 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1200132131747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600066065573 + 600066065574.

It is an arithmetic number, because the mean of its divisors is an integer number (600066065574).

Almost surely, 21200132131147 is an apocalyptic number.

1200132131147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200132131147 is an equidigital number, since it uses as much as digits as its factorization.

1200132131147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 1200132131147 its reverse (7411312310021), we get a palindrome (8611444441168).

The spelling of 1200132131147 in words is "one trillion, two hundred billion, one hundred thirty-two million, one hundred thirty-one thousand, one hundred forty-seven".