Base | Representation |
---|---|
bin | 110111111000101011… |
… | …0011100100001100011 |
3 | 102110202221012211110022 |
4 | 1233301112130201203 |
5 | 3431241401410201 |
6 | 131044445424055 |
7 | 11446020206135 |
oct | 1576126344143 |
9 | 373687184408 |
10 | 120013310051 |
11 | 46996426168 |
12 | 1b31426b02b |
13 | b417b9773b |
14 | 5b4700d055 |
15 | 31c623441b |
hex | 1bf159c863 |
120013310051 has 2 divisors, whose sum is σ = 120013310052. Its totient is φ = 120013310050.
The previous prime is 120013310047. The next prime is 120013310063. The reversal of 120013310051 is 150013310021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120013310051 - 22 = 120013310047 is a prime.
It is not a weakly prime, because it can be changed into another prime (120013310951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006655025 + 60006655026.
It is an arithmetic number, because the mean of its divisors is an integer number (60006655026).
Almost surely, 2120013310051 is an apocalyptic number.
120013310051 is a deficient number, since it is larger than the sum of its proper divisors (1).
120013310051 is an equidigital number, since it uses as much as digits as its factorization.
120013310051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 120013310051 its reverse (150013310021), we get a palindrome (270026620072).
The spelling of 120013310051 in words is "one hundred twenty billion, thirteen million, three hundred ten thousand, fifty-one".
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