Base | Representation |
---|---|
bin | 10001011101101101100… |
… | …011111110101110100111 |
3 | 11020201202101220020111010 |
4 | 101131231203332232213 |
5 | 124130333302232403 |
6 | 2315200045113303 |
7 | 152464303613610 |
oct | 21355543765647 |
9 | 4221671806433 |
10 | 1200134024103 |
11 | 422a79407413 |
12 | 174716558833 |
13 | 892312b2001 |
14 | 42130254c07 |
15 | 21341861603 |
hex | 1176d8feba7 |
1200134024103 has 64 divisors (see below), whose sum is σ = 1953653990400. Its totient is φ = 640055623680.
The previous prime is 1200134024081. The next prime is 1200134024113. The reversal of 1200134024103 is 3014204310021.
It is not a de Polignac number, because 1200134024103 - 26 = 1200134024039 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 1200134024103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200134024113) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 25637503 + ... + 25684271.
It is an arithmetic number, because the mean of its divisors is an integer number (30525843600).
Almost surely, 21200134024103 is an apocalyptic number.
1200134024103 is a deficient number, since it is larger than the sum of its proper divisors (753519966297).
1200134024103 is a wasteful number, since it uses less digits than its factorization.
1200134024103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47752.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 1200134024103 its reverse (3014204310021), we get a palindrome (4214338334124).
The spelling of 1200134024103 in words is "one trillion, two hundred billion, one hundred thirty-four million, twenty-four thousand, one hundred three".
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