Base | Representation |
---|---|
bin | 11011010010011011110111… |
… | …111001011110011101001100 |
3 | 120201221020110102200211011110 |
4 | 123102123313321132131030 |
5 | 111212302422104133030 |
6 | 1103125422123452020 |
7 | 34164510102462153 |
oct | 3322336771363514 |
9 | 521836412624143 |
10 | 120014135224140 |
11 | 35270788632333 |
12 | 11563663087010 |
13 | 51c7390a63121 |
14 | 218ca024a659a |
15 | dd1c9a59a1b0 |
hex | 6d26f7e5e74c |
120014135224140 has 192 divisors, whose sum is σ = 345925819330560. Its totient is φ = 31075795445760.
The previous prime is 120014135224121. The next prime is 120014135224183. The reversal of 120014135224140 is 41422531410021.
It is a super-2 number, since 2×1200141352241402 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 120014135224098 and 120014135224107.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2083803184 + ... + 2083860776.
It is an arithmetic number, because the mean of its divisors is an integer number (1801696975680).
Almost surely, 2120014135224140 is an apocalyptic number.
120014135224140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120014135224140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (172962909665280).
120014135224140 is an abundant number, since it is smaller than the sum of its proper divisors (225911684106420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120014135224140 is a wasteful number, since it uses less digits than its factorization.
120014135224140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64952 (or 64950 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 30.
Adding to 120014135224140 its reverse (41422531410021), we get a palindrome (161436666634161).
The spelling of 120014135224140 in words is "one hundred twenty trillion, fourteen billion, one hundred thirty-five million, two hundred twenty-four thousand, one hundred forty".
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